50x^2-24x-32=0

Solution for 50x^2-24x-32=0 equation:

50x^2-24x-32=0

a = 50; b = -24; c = -32;
Δ = b2-4ac
Δ = -242-4·50·(-32)
Δ = 6976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6976}=\sqrt{64*109}=\sqrt{64}*\sqrt{109}=8\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8\sqrt{109}}{2*50}=\frac{24-8\sqrt{109}}{100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8\sqrt{109}}{2*50}=\frac{24+8\sqrt{109}}{100}
$